How do you differentiate #(5-x^-1)^(1/3)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Gió Feb 10, 2015 You can use the Chain Rule. You differentiate first the the #1/3# power (leaving the argument as it is) and then multiply times the argument differentiated: #1/3(5-x^-1)^(1/3-1)*x^-2=# #1/3(5-x^-1)^(-2/3)*x^-2=# #=1/3*1/(5-x^-1)^(2/3)*1/x^2# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2686 views around the world You can reuse this answer Creative Commons License