How do you differentiate $A = \frac{\sqrt{3}}{4} s^{2} + \frac{3 π}{8} s^{2}$ $A=sqrt3/4s^2+(3pi)/8s^2$ ?

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Answer 1 · 2018-04-25T01:06:59

$\frac{2 \sqrt{3}}{4} s + \frac{6 π}{8} s$ $(2sqrt3)/4s+(6pi)/8s$

We got: $A = \frac{\sqrt{3}}{4} s^{2} + \frac{3 π}{8} s^{2}$ $A=sqrt3/4s^2+(3pi)/8s^2$

Differentiating respect to $s$ $s$ , we get:

$(dA)/(ds)=sqrt3/4(s^2)'+(3pi)/8(s^2)'$

$=(sqrt3)/4*2s+(3pi)/8*2s$

$=(2sqrt3)/4s+(6pi)/8s$

How do you differentiate A=sqrt3/4s^2+(3pi)/8s^2A=√34s2+3π8s2A=sqrt3/4s^2+(3pi)/8s^2?