Question

How do you differentiate `e^tanx`?

Answer 1

`e^(tanx)*sec^2x`

Explanation:

`(1)d/(dx)(e^x)=e^x`
`(2)d/(dx)(tanx)=sec^2x`
So,
`y=e^tanxrArr(dy)/(dx)=e^(tanx)*d/(dx)(tanx),Apply(1)`
`=>(dy)/(dx)=e^(tanx)*sec^2x,Apply(2)`