How do you differentiate $f (x) = 2 sin x cos x$ $f(x)=2sinxcosx$ ?

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Answer 1 · 2016-11-02T20:19:58

$f'(x) = 2cos(2x)$

Use the identity $2sinthetacostheta = sin2theta$ to rewrite the function.

$f(x) = sin2x$

Now, use the chain rule to differentiate.

Let $y = sinu$ and $u = 2x$ . $y' = cosu$ and $u' = 2$ .

$dy/dx = cosu xx 2 = cos(2x) xx 2 = 2cos(2x)$

Hopefully this helps!

How do you differentiate f(x)=2sinxcosxf(x)=2sinxcosxf(x)=2sinxcosx?