How do you differentiate $f(x)=3-7x^3+3x^7$ ?

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Answer 1 · 2016-11-02T10:21:49

Therefore, differentiating $f(x)=3-7x^3+3x^7.$ w.r.t $x$ , comes to be $-21x^2+21x^6.$ (answer).

Let, $y=f(x)=3-7x^3+3x^7.$

$:.$ Differentiating $y$ w.r.t $x$ is,

$d/(dx)(y)=dy/dx=d/(dx)(3-7x^3+3x^7).$
$:.dy/dx=0-7*3*x^(3-1)+3*7*x^(7-1).$
$:.dy/dx=-21x^2+21x^6.$

Therefore, differentiating $y$ w.r.t $x$ , comes to be $-21x^2+21x^6.$ (answer).

How do you differentiate f(x)=3-7x^3+3x^7f(x)=3-7x^3+3x^7?