Question

How do you differentiate `f(x)= (4x^2+5)(3x-5)` using the product rule?

Answer 1

`d/(d x) f(x)=36x^2-40x+15`

Explanation:

`f(x)=(4x^2+5)(3x-5)`
`d/(d x) f(x)=(4x^2+5)^' * (3x-5)+(3x-5) ^ ' * (4x^2+5)`
`d/(d x) f(x)=8x(3x-5)+3(4x^2+5)`
`d/(d x) f(x)=24x^2-40x+12x^2+15`
`d/(d x) f(x)=36x^2-40x+15`