How do you differentiate #f(x) = 5(x^2-4 )^(2) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Lucy May 7, 2018 #f'(x)=20x(x^2-4)# Explanation: #f(x)=5(x^2-4)^2# #f'(x)=5*2(x^2-4)*2x# #f'(x)=20x(x^2-4)# The chain rule is given by: #F(x)=f(g(x))# #F'(x)=f'(g(x))timesg'(x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1341 views around the world You can reuse this answer Creative Commons License