How do you differentiate $f(x)= 5/x^3 - 3/ x^(1/3)$ ?

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Answer 1 · 2018-04-21T12:58:19

$color(blue)(f'(x) = -15/x^4 + 1/x^(4/3)$

$f(x) = 5/x^3 - 3 / x^(1/3)$

$f(x) = 5 * x^-3 - 3 * x^-(1/3)$

$(d/(dx)) x^n = n * x^(n-1)$

$:. f'(x) = 5 * -3 * x^-4 - 3 * -(1/3) * x ^-(4/3)$

$f'(x) = -15 x^-4 + x^-(4/3)$

$=> -15/x^4 + 1/x^(4/3)$

How do you differentiate f(x)= 5/x^3 - 3/ x^(1/3)f(x)= 5/x^3 - 3/ x^(1/3)?