How do you differentiate #f(x)= 5/x^3 - 3/ x^(1/3)#? Calculus Basic Differentiation Rules Power Rule 1 Answer sankarankalyanam Apr 21, 2018 #color(blue)(f'(x) = -15/x^4 + 1/x^(4/3)# Explanation: #f(x) = 5/x^3 - 3 / x^(1/3)# #f(x) = 5 * x^-3 - 3 * x^-(1/3)# #(d/(dx)) x^n = n * x^(n-1)# #:. f'(x) = 5 * -3 * x^-4 - 3 * -(1/3) * x ^-(4/3)# #f'(x) = -15 x^-4 + x^-(4/3)# #=> -15/x^4 + 1/x^(4/3)# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1395 views around the world You can reuse this answer Creative Commons License