How do you differentiate #f(x)=csc(sqrt(x)) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Leland Adriano Alejandro Jan 15, 2016 #f' (x) = - (csc sqrt(x) cot sqrt(x))/(2 sqrt(x))# Explanation: #f(x) = csc sqrt(x)# #f' (x) = - csc sqrt(x) * cot sqrt(x) * 1/(2 sqrt(x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 4536 views around the world You can reuse this answer Creative Commons License