How do you differentiate # f(x)= (e^x-e^-x) / 2#?

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Answer 1 · 2016-08-01T09:30:03

#= (e^x+e^-x) / 2#

#d/dx ((e^x-e^-x) / 2)#

#= d/dx (e^x/2) - d/dx( (e^-x) / 2)#

#= e^x/2 - (-e^-x) / 2#

#= (e^x+e^-x) / 2#

or if you like.....

#d/dx ((e^x-e^-x) / 2)#

#= d/dx sinh x#

#= cosh x#

#= (e^x+e^-x) / 2#