How do you differentiate $f(x) = e^xlnx$ ?

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Answer 1 · 2016-05-24T06:35:38

$d f(x)=(e^x/x+e^x*l n (e)*l n(x))*d x$

$f(x)=e^x*l n x ?$

$d/(d x) (e^x)=e^x*l n(e)$

$d/(d x) l n(x)=1/x$

$y=a.b$

$y^'=a^'*b+b^'*a$

$d f(x)=(e^x*l n(e)*l n (x)+1/x*e^x)* d x$

$"or:"$

$d f(x)=(e^x/x+e^x*l n (e)*l n(x))*d x$

How do you differentiate f(x) = e^xlnxf(x) = e^xlnx?