Question

How do you differentiate `f(x)=ln(x^2-sqrt(2x+8)))` using the chain rule?

Answer 1

`f'(x)=2/(x^2-sqrt(2x+8)) * (2x-1/2(2x+8)^(-1/2))`

Explanation:

`f'(x)=1/(x^2-sqrt(2x+8)) * (2x-1/2(2x+8)^(-1/2)) * (2)`