Question

How do you differentiate `f(x)= ln(x^2-x)`?

Answer 1

Using chain rule, which states that `(dy)/(dx)=(dy)/(du)(du)/(dx)`, let's rename `u=x^2-x`

Explanation:

`(df(x))/(dx)=(1/u)(2x-1)`

`(df(x))/(dx)=(2x-1)/(x^2-x)`