How do you differentiate f(x)=sin(4x^2) f(x)=sin(4x2) using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Jim G. Jan 9, 2016 8xcos(4x^2 ) 8xcos(4x2) Explanation: using the chain rule gives : f'(x) = cos(4x^2). d/dx (4x^2 ) = cos(4x^2)(8x ) rArr f'(x) = 8xcos(4x^2 ) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 6214 views around the world You can reuse this answer Creative Commons License