Question

How do you differentiate `f(x)=sin2x^3`?

Answer 1

`f'(x)=6x^2cos2x^3`

Explanation:

differentiate using the `color(blue)"chain rule"`

`"Given " f(x)=g(h(x))" then"`

`• f'(x)=g'(h(x))xxh'(x)larr" chain rule"`

`rArrf'(x)=cos2x^3xxd/dx(2x^3)`

`color(white)(rArrf'(x))=6x^2cos2x^3`