Question

How do you differentiate `f(x)=-sinsqrt(1/(x^2))` using the chain rule?

Answer 1

`f'(x)=-cos(1/x)/x^2`

Explanation:

`f(x)=-sinsqrt(1/x^2) = -sin (x^-2)^(1/2)=sinx^-1`

`f'(x)=cos(1/x)*-1/x^2`

`f'(x)=-cos(1/x)/x^2`