Question

How do you differentiate `f(x)=sqrt(3+x^2)` using the chain rule?

Answer 1

You can do it like this:

Explanation:

`f(x)=sqrt(3+x^2)`

`:.f(x)=(3+x^2)^(1/2)`

`:.f'(x)=1/2(3+x^2)^(-1/2)xx2x`

`:.f'(x)=(cancel(2)x)/(cancel(2)sqrt(3+x^2))`

`:.f'(x)=(x)/(sqrt(3+x^2))`