Question

How do you differentiate `f(x)=sqrtcos(7-4x)` using the chain rule?

Answer 1

`f'(x)=(4sin(7-4x))/(2sqrt(cos(7-4x))`

Explanation:

`f(x)=sqrt(cos(7-4x))`
`f(x)=(cos(7-4x))^(1/2)`
`f'(x)=1/2 (cos(7-4x))^(-1/2) * -sin(7-4x) * -4`
`f'(x)=(4sin(7-4x))/(2sqrt(cos(7-4x))`