Question

How do you differentiate `f(x)=tan(1-3x^2)` using the chain rule?

Answer 1

`(-6x)sec^2(1 - 3x^2 )`

Explanation:

applying the chain rule as follows :

`f'(x) = sec^2(1 - 3x^2).d/dx(1 - 3x^2 )`

`f'(x) = sec^2(1 - 3x^2).(- 6x )`

`rArr f'(x) =(-6x)sec^2(1 - 3x^2 )`