How do you differentiate #f(x)=xe^(-2x)# using the product rule? Calculus Basic Differentiation Rules Product Rule 1 Answer Binayaka C. Apr 17, 2018 #f'(x)=e^(-2 x)(1-2 x) # Explanation: # f(x) = x e^(-2 x)# ; Product rule: #(f g)' = f'g+f g'# #f'(x)=1*e^(-2 x)+ x e^(-2 x)*(-2) # #f'(x)=e^(-2 x)-2 x e^(-2 x) # or #f'(x)=e^(-2 x)(1-2 x) # [Ans] Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 6764 views around the world You can reuse this answer Creative Commons License