Question

How do you differentiate `G(x)=(1/2x)^5`?

Answer 1

`(dG)/dx=5/32 x^4`

Explanation:

if `y=x^n` then `dy/dx=nx^(n-1)`

In our problem
`G(x)=(1/2)^5 x^5`
`G(x)=(1/32) x^5`

`:. (dG)/dx=(1/32)(5x^(5-1))`
`:. (dG)/dx=5/32 x^4`