Question

How do you differentiate `g(x)=(1+4x)^5(3+x-x^2)^8`?

Answer 1

`g'(x)=8(4x+1)^5(-x^2+x+3)^7(-2x+1)+20(4x+1)^4(-x^2+x+3)^8`

Explanation:

`g(x)=(4x+1)^5(-x^2+x+3)^8`

`g'(x)=(4x+1)^5(8)(-x^2+x+3)^7(-2x+1)+5(4x+1)^4(4)(-x^2+x+3)^8`

`g'(x)=8(4x+1)^5(-x^2+x+3)^7(-2x+1)+20(4x+1)^4(-x^2+x+3)^8`