Question

How do you differentiate `G(x) = intsqrtt sint dt` from `sqrt(x)` to `x^3`?

Answer 1

You have

`G(x)=int_sqrt(x)^(x^3)sqrt(t)*sintdt=>d(G(x))/dx=sqrt(x^3)*sin(x^3)*(3x^2)-sqrt(sqrt(x))*sin(sqrt(x))*(1/(2*sqrt(x)))`