Question

How do you differentiate `ln[ (2x^3)-(3x^2)+(7) ]`?

Answer 1

`1/(2*x^3-3*x^2+7)*(6*x^2-6*x)`

Explanation:

Using the fact that`(ln(x))'=1/x` and the chain rule we get

`1/(2x^3-3x^2+7)*(6x^2-6x)`