How do you differentiate #log_2(3x-1)#?
1 Answer
Apr 20, 2017
Explanation:
For this problem, the following formula will be used
What this basically means, is that the derivative of a log base a of some function equals 1 over that function times the natural log of base a times the derivative of
-
#d/dxlog_2(3x-1)# -
#=1/((3x-1)*ln2)*3# -
#=3/((3x-1)*ln2)#