How do you differentiate #sin3x^2#?
1 Answer
Jun 21, 2016
Explanation:
differentiate using the
#color(blue)"chain rule"#
#d/dx[f(g(x))]=f'(g(x)).g'(x)........ (A)#
#"------------------------------------------"#
#f(g(x))=sin3x^2rArrf'(g(x))=cos3x^2#
#g(x)=3x^2rArrg'(x)=6x#
#"--------------------------------------------"#
Substitute these values into (A)
#rArrd/dx[sin3x^2]=6xcos3x^2#
