How do you differentiate $f(x) = tanx+cscx$ ?

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Answer 1 · 2017-11-09T04:00:52

$f'(x)=sec^2x-cscxcotx$

Take each individual derivative, then combine

$d/dx(tanx)=sec^2x$

$d/dx(cscx)=-cscxcotx$

$:.f'(x)=sec^2x-cscxcotx$

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