How do you differentiate $u=root5(t)+4sqrt(t^5)$ ?

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Answer 1 · 2016-12-24T18:18:26

$(du)/(dt)=1/(5t^(4/5))+2/sqrt(t^5)$

$u=t^(1/5)+4(t^5)^(1/2)$

If $y=ax^n$ then the derivative, $dy/dx=nax^(n-1)$

Using this, $(du)/(dt)=1/5t^(-4/5)+4(1/2)(t^5)^(-1/2)=1/(5t^(4/5))+2/sqrt(t^5)$

How do you differentiate u=root5(t)+4sqrt(t^5)u=root5(t)+4sqrt(t^5)?