How do you differentiate #(x^2)-2xy+y^3#?

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Answer 1 · 2015-08-10T18:07:38

#2(x+y)+dy/dx(2x+3y^2)#

By implicit differentiation each term differentiates to:

#d/dx(x^2)=2x#

#d/dx(2xy)=2y+2xdy/dx#

#d/dy(y^3)=3y^2dy/dx#

Combing these terms we have:

#2(x+y)+dy/dx(2x+3y^2)#