How do you differentiate $x^{4} + 2 y^{2} = 8$ $x^4+2y^2=8$ ?

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How do you differentiate $x^{4} + 2 y^{2} = 8$ $x^4+2y^2=8$ ?

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Answer 1 · 2015-07-05T01:39:13

I found: $\frac{d y}{d x} = - \frac{x^{3}}{y}$ $(dy)/(dx)=-x^3/y$

Explanation:

You use implicit differentiation remembering that $y$ $y$ is a function of $x$ $x$ .
So:
$4 x^{3} + 4 y \frac{d y}{d x} = 0$ $4x^3+4ycolor(red)((dy)/(dx))=0$
$(dy)/(dx)=-cancel(4)x^3/(cancel(4)y)=-x^3/y$

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How do you differentiate $x^{4} + 2 y^{2} = 8$ $x^4+2y^2=8$ ?

1 Answer

Explanation:

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How do you differentiate x^4+2y^2=8x4+2y2=8x^4+2y^2=8?

1 Answer

Explanation:

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How do you differentiate $x^{4} + 2 y^{2} = 8$ $x^4+2y^2=8$ ?