How do you differentiate $y = 3 x^5 - 2e^x + 2cosx$ ?

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Answer 1 · 2016-05-06T14:12:06

$y' = 15x^4-2e^x-2*sin x$

Differentiate each term of the right side of the equation with respect to x

$y=3x^5-2e^x+2cos x$

$dy/dx=d/dx(3*x^5)-d/dx(2*e^x)+d/dx(2*cos x)$

$dy/dx=3*5x^(5-1)-2*e^x-2*sin x$

$dy/dx=15x^4-2*e^x-2*sin x$

God bless....I hope the explanation is useful.

How do you differentiate y = 3 x^5 - 2e^x + 2cosx y = 3 x^5 - 2e^x + 2cosx?