Question

How do you differentiate `y=cosln4x^3`?

Answer 1

`dy/dx=(-3sin(ln(4x^3)))/x`

Explanation:

`y=cosln4x^3`

Use chain rule `(f(g(x))' = f'(g(x)) * g'(x)`

`dy/dx=-sin(ln(4x^3))*1/(4x^3) *12x^2`

`dy/dx=-sin(ln(4x^3)) *3/x`

`dy/dx=(-3sin(ln(4x^3)))/x`