How do you differentiate # y=e^ (-4x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Bdub Mar 10, 2016 #y'= -4e^(-4x)# Explanation: #y'=e^u * u' = e^(-4x) * -4 = -4e^(-4x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 8870 views around the world You can reuse this answer Creative Commons License