Question

How do you differentiate `y=e^(sqrt(x^2+2))`?

Answer 1

`color(blue)(y’ = (x*e^sqrt(x^2+2)) / sqrt(x^2+2)`

Explanation:

`y = e^sqrt(x^2 + 2)`

y’ = (d/(dx)) e^sqrt(x^2 + 2)#

`y’ = e^sqrt(x^2 + 2) * (1/(2*sqrt(x^2+2))) * 2x`

`color(blue)(y’ = (x*e^sqrt(x^2+2)) / sqrt(x^2+2)`