How do you differentiate $y = e^{- x} sin x$ $y= e^-x sinx$ ?

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Answer 1 · 2016-08-02T00:27:14

I found: $y'=e^-x[cos(x)-sin(x)]$

You can use the Product Rule to get:
$y'=-e^-xsin(x)+e^-xcos(x)=e^-x[cos(x)-sin(x)]$

How do you differentiate y= e^-x sinxy=e−xsinxy= e^-x sinx?