How do you differentiate #y=(e^x(x^2-7))#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer AJ Speller Oct 5, 2016 #f'(x)=e^x(x^2+2x-7)# Explanation: You have to use the Product Rule #f'(x)=uv'+u'v# #u=e^x# #u'=e^x# #v=x^2-7# #v'=2x# #f'(x)=e^x2x+e^x(x^2-7)# Factor out #e^x# #f'(x)=e^x(x^2+2x-7)# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 1557 views around the world You can reuse this answer Creative Commons License