Question

How do you differentiate `y=lnx(x^5+10x^2-19)`?

Answer 1

`(dy)/(dx)=1/x(x^5+10x^2-19)+5x(x^3+4)lnx`

Explanation:

Using product rule, if `y=lnx(x^5+10x^2-19)`

`(dy)/(dx)=1/x(x^5+10x^2-19)+lnx(5x^4+20x)`

= `1/x(x^5+10x^2-19)+5x(x^3+4)lnx`