How do you differentiate y=logx2? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions without Base e 1 Answer Shwetank Mauria Jul 11, 2017 dydx=−ln2x(lnx)2 Explanation: As y=logx2, we have y=ln2lnx Hence assuming g(f(x))=1f(x), where f(x)=lnx dydx=ln2×dg(x)df(x)×dfdx =ln2×(−1(lnx)2)×1x =−ln2x(lnx)2 Answer link Related questions What is the derivative of f(x)=logb(g(x)) ? What is the derivative of f(x)=log(x2+x) ? What is the derivative of f(x)=log4(ex+3) ? What is the derivative of f(x)=x⋅log5(x) ? What is the derivative of f(x)=e4x⋅log(1−x) ? What is the derivative of f(x)=log(x)x ? What is the derivative of f(x)=log2(cos(x)) ? What is the derivative of f(x)=log11(tan(x)) ? What is the derivative of f(x)=√1+log3(x) ? What is the derivative of f(x)=(log6(x))2 ? See all questions in Differentiating Logarithmic Functions without Base e Impact of this question 1821 views around the world You can reuse this answer Creative Commons License