Question

How do you differentiate `y = sin (x^2+2)` using the chain rule?

Answer 1

`y'=2x cos(x^2+2)`

Explanation:

To differentiate this, we have to use `D_x Sinu= cosx D_x u`
So `y= sin(x^2+ 2)`
`y'= cos(x^2+2)(2x)`
`y'=2x cos(x^2+2)`