Question

How do you differentiate `y=sin(x^2)(cos(x^2)` using the chain rule?

Answer 1

`(dy)/(dx)=2xcos(2x^2)`

Explanation:

`y=sin(x^2)cos(x^2)`

= `1/2xx2sin(x^2)cos(x^2)`

= `1/2sin(2x^2)`

Hence, using chain rule

`(dy)/(dx)=1/2xxcos(2x^2)xx4x`

= `2xcos(2x^2)`