How do you divide $(10 r^{3} - 22 r^{2} - 17 r - 21) \div (r - 3)$ $(10r^3-22r^2-17r-21)div(r-3)$ using synthetic division?

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How do you divide $(10 r^{3} - 22 r^{2} - 17 r - 21) \div (r - 3)$ $(10r^3-22r^2-17r-21)div(r-3)$ using synthetic division?

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Answer 1 · 2016-10-30T07:20:27

The answer is $= 10 r^{2} + 8 r + 7$ $=10r^2+8r+7$

Explanation:

Let's do the division
$10 r^{3} - 22 r^{2} - 17 r - 21$ $10r^3-22r^2-17r-21$ $a a a a$ $color(white)(aaaa)$ $∣$ $∣$ $r - 3$ $r-3$
$10 r^{3} - 30 r^{2}$ $10r^3-30r^2$ $a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaa)$ $∣$ $∣$ $10 r^{2} + 8 r + 7$ $10r^2+8r+7$
$a a$ $color(white)(aa)$ $0 + 8 r^{2} - 17 r$ $0+8r^2-17r$
$a a a a$ $color(white)(aaaa)$ $+ 8 r^{2} - 24 r$ $+8r^2-24r$
$a a a a a a a$ $color(white)(aaaaaaa)$ $0 + 7 r - 21$ $0+7r-21$
$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $7 r - 21$ $7r-21$
$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $0 - 0$ $0-0$

So we have $\frac{10 r^{3} - 22 r^{2} - 17 r - 21}{r - 3} = 10 r^{2} + 8 r + 7$ $(10r^3-22r^2-17r-21)/(r-3)=10r^2+8r+7$

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How do you divide $(10 r^{3} - 22 r^{2} - 17 r - 21) \div (r - 3)$ $(10r^3-22r^2-17r-21)div(r-3)$ using synthetic division?

1 Answer

Explanation:

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How do you divide (10r^3-22r^2-17r-21)div(r-3)(10r3−22r2−17r−21)÷(r−3)(10r^3-22r^2-17r-21)div(r-3) using synthetic division?

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Explanation:

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How do you divide $(10 r^{3} - 22 r^{2} - 17 r - 21) \div (r - 3)$ $(10r^3-22r^2-17r-21)div(r-3)$ using synthetic division?