Question

How do you divide `10x^3+mx^2-x+10` by `5x-3`?

Answer 1

Use synthetic division to find:

`(10x^3+mx^2-x+10)/(5x-3) = 2x^2 + (m-6)/5x+(3m-23)/25`

with remainder `(9m+121)/25`

Explanation:

Let's use synthetic division: