How do you divide $10 x^{3} + m x^{2} - x + 10$ $10x^3+mx^2-x+10$ by $5 x - 3$ $5x-3$ ?

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How do you divide $10 x^{3} + m x^{2} - x + 10$ $10x^3+mx^2-x+10$ by $5 x - 3$ $5x-3$ ?

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Answer 1 · 2015-08-16T13:35:58

Use synthetic division to find:

$\frac{10 x^{3} + m x^{2} - x + 10}{5 x - 3} = 2 x^{2} + \frac{m - 6}{5} x + \frac{3 m - 23}{25}$ $(10x^3+mx^2-x+10)/(5x-3) = 2x^2 + (m-6)/5x+(3m-23)/25$

with remainder $\frac{9 m + 121}{25}$ $(9m+121)/25$

Explanation:

Let's use synthetic division:

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How do you divide $10 x^{3} + m x^{2} - x + 10$ $10x^3+mx^2-x+10$ by $5 x - 3$ $5x-3$ ?

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How do you divide $10 x^{3} + m x^{2} - x + 10$ $10x^3+mx^2-x+10$ by $5 x - 3$ $5x-3$ ?