How do you divide #24x^4+31^3+7x^2+4x+10# by #3x+2#?

Question

1744 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-19T07:29:13

The Quotient Poly. is #(8x^3+5x^2-x+2)#.

The Reminder is #6#.

it is assumed that the Dividend Poly. is

# : p(x)=24x^4+31x^3+7x^2+4x+10#, instead of as stated in the

Problem # : 24x^4+31^3+7x^2+4x+10#.

We split the terms of #p(x)# as under :

#p(x)=ul(24x^4+16x^3)+ul(15x^3+10x^2)-ul(3x^2-2x)+ul(6x+4)+6#

#=8x^3(3x+2)+5x^2(3x+2)-x(3x+2)+2(3x+2)+6#

#=(3x+2)(8x^3+5x^2-x+2)+6#

Therefore, dividing #p(x)# by #(3x+2)#, the Quotient Poly. is

#(8x^3+5x^2-x+2)# and the Reminder is #6#.

Enjoy Maths.!