How do you divide $(26 - 43 k - 83 k^{2} + 9 k^{3}) \div (7 + 9 k)$ $(26-43k-83k^2+9k^3)div(7+9k)$ using synthetic division?

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How do you divide $(26 - 43 k - 83 k^{2} + 9 k^{3}) \div (7 + 9 k)$ $(26-43k-83k^2+9k^3)div(7+9k)$ using synthetic division?

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Answer 1 · 2018-01-29T01:47:38

$9 k^{2} - 90 k + 27 + \frac{5}{k + (\frac{7}{9})}$ $color(green)(9k^2 - 90k + 27 + 5/ (k + (7/9)))$

Explanation:

$\frac{9 k^{3} - 83 k^{2} - 43 k + 26}{9 k + 7}$ $(9k^3 - 83k^2-43k+26) / (9k + 7)$

$- \frac{7}{9} a a ∣ a a 9 a a - 83 a a - 43 a a a a a a a 26$ $color(white)()-7/9color(white)(aa)|color(white)(aa)9color(white)(aa)-83color(white)(aa)-43color(white)(aaaaaaa)26$
$a a a a a a ∣$ $color(white)(aaaaaa)|$
$a a a a a a ∣ a ⏐ ↓ a a - 7 a a a a 70 a a a a a - 21$ $color(white)(aaaaaa)|color(white)(a)darrcolor(white)(aa)-7color(white)(aaaa)70color(white)(aaaaa)-21$
$a a a a a a - - - - - - - - - - -$ $color(white)(aaaaaa)-----------$

$a a a a a a a a a a 9 a a - 90 a a a a 27 a a a a a a a a 5$ $color(white)(aaaaaaaaaa)9color(white)(aa)-90color(white)(aaaa)27color(white)(aaaaaaaa)5$

Answer : $9 k^{2} - 90 k + 27 + \frac{5}{k + (\frac{7}{9})}$ $color(green)(9k^2 - 90k + 27 + 5/ (k + (7/9)))$

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How do you divide $(26 - 43 k - 83 k^{2} + 9 k^{3}) \div (7 + 9 k)$ $(26-43k-83k^2+9k^3)div(7+9k)$ using synthetic division?

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Explanation:

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How do you divide (26−43k−83k2+9k3)÷(7+9k)(26-43k-83k^2+9k^3)div(7+9k) using synthetic division?

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Explanation:

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How do you divide $(26 - 43 k - 83 k^{2} + 9 k^{3}) \div (7 + 9 k)$ $(26-43k-83k^2+9k^3)div(7+9k)$ using synthetic division?