How do you divide $2m^2 + 3m - 14$ by $2m+7$ ?

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Answer 1 · 2015-07-13T20:11:16

$(2m^2 +3m -14)/(2m+7) = 2m^2 – 14m + 101 - 721/(m+7)$

You use the process of long division.

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So,

$(2m^2 + 3m -14)/(2m+7) = 2m^2 – 14m + 101 - 721/(m+7)$

Check:

$(m+7)(2m^2 – 14m + 101 + 721/(m+7)) =(m+7)( 2m^2 – 14m +101) -721= 2m^3 –cancel(14m²) +101m +cancel(14m²) -98m +707-721 = 2m^3 +3m -14$

How do you divide 2m^2 + 3m - 142m^2 + 3m - 14 by 2m+72m+7?