How do you divide $(2 x^{3} - 11 x^{2} + 9 x - 20) \div (x - 5)$ $(2x^3-11x^2+9x-20)div(x-5)$ using synthetic division?

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How do you divide $(2 x^{3} - 11 x^{2} + 9 x - 20) \div (x - 5)$ $(2x^3-11x^2+9x-20)div(x-5)$ using synthetic division?

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Answer 1 · 2017-08-13T05:04:58

The remainder is $0$ $color(red)(0)$ and the quotient is $= 2 x^{2} - x + 4$ $=2x^2-x+4$

Explanation:

Let's perform the synthetic division

$a a a a$ $color(white)(aaaa)$ $5$ $5$ $a a a a a a$ $color(white)(aaaaaa)$ $∣$ $|$ $a a$ $color(white)(aa)$ $2$ $2$ $a a a a a a a$ $color(white)(aaaaaaa)$ $- 11$ $-11$ $a a a a a a$ $color(white)(aaaaaa)$ $9$ $9$ $a a a a a a a$ $color(white)(aaaaaaa)$ $- 20$ $-20$
$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $- - - - - - - - - - - -$ $------------$

$a a a a$ $color(white)(aaaa)$ $a a a a a a a$ $color(white)(aaaaaaa)$ $∣$ $|$ $a a a a$ $color(white)(aaaa)$ $a a a a a a a$ $color(white)(aaaaaaa)$ $10$ $10$ $a a a a a a$ $color(white)(aaaaaa)$ $- 5$ $-5$ $a a a a a a a a$ $color(white)(aaaaaaaa)$ $20$ $20$
$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $- - - - - - - - - - - -$ $------------$

$a a a a$ $color(white)(aaaa)$ $a a a a a a a$ $color(white)(aaaaaaa)$ $∣$ $|$ $a a a$ $color(white)(aaa)$ $2$ $2$ $a a a a a a$ $color(white)(aaaaaa)$ $- 1$ $-1$ $a a a a a a a a$ $color(white)(aaaaaaaa)$ $4$ $4$ $a a a a a a a a$ $color(white)(aaaaaaaa)$ $0$ $color(red)(0)$

The remainder is $0$ $color(red)(0)$ and the quotient is $= 2 x^{2} - x + 4$ $=2x^2-x+4$

$\frac{2 x^{3} - 11 x^{2} + 9 x - 20}{x - 5} = 2 x^{2} - x + 4$ $(2x^3-11x^2+9x-20)/(x-5)=2x^2-x+4$

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How do you divide $(2 x^{3} - 11 x^{2} + 9 x - 20) \div (x - 5)$ $(2x^3-11x^2+9x-20)div(x-5)$ using synthetic division?

1 Answer

Explanation:

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How do you divide (2x3−11x2+9x−20)÷(x−5)(2x^3-11x^2+9x-20)div(x-5) using synthetic division?

1 Answer

Explanation:

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How do you divide $(2 x^{3} - 11 x^{2} + 9 x - 20) \div (x - 5)$ $(2x^3-11x^2+9x-20)div(x-5)$ using synthetic division?