How do you divide $(2 x^{3} - 7 x^{2} - 17 x - 3) \div (2 x + 3)$ $(2x^3-7x^2-17x-3)div(2x+3)$ using long division?

Question

How do you divide $(2 x^{3} - 7 x^{2} - 17 x - 3) \div (2 x + 3)$ $(2x^3-7x^2-17x-3)div(2x+3)$ using long division?

1 Answer

Impact of this question

2572 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-12T08:11:05

The remainder is $= 0$ $=0$ and the quotient is $= x^{2} - 5 x - 1$ $=x^2-5x-1$

Explanation:

Let's go for a long division

$a a a a$ $color(white)(aaaa)$ $2 x^{3} - 7 x^{2} - 17 x - 3$ $2x^3-7x^2-17x-3$ $a a a a$ $color(white)(aaaa)$ $∣$ $∣$ $2 x + 3$ $color(blue)(2x+3)$

$a a a a$ $color(white)(aaaa)$ $2 x^{3} + 3 x^{2}$ $2x^3+3x^2$ $a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $∣$ $x^{2} - 5 x - 1$ $color(red)(x^2-5x-1)$

$a a a a a$ $color(white)(aaaaa)$ $0 - 10 x^{2} - 17 x$ $0-10x^2-17x$

$a a a a a a a$ $color(white)(aaaaaaa)$ $- 10 x^{2} - 15 x$ $-10x^2-15x$

$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $0 - 2 x - 3$ $0-2x-3$

$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $- 2 x - 3$ $-2x-3$

$a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaa)$ $- 0 - 0$ $-0-0$

The remainder is $= 0$ $=0$ and the quotient is $= x^{2} - 5 x - 1$ $=x^2-5x-1$

$\frac{2 x^{3} - 7 x^{2} - 17 x - 3}{2 x + 3} = x^{2} - 5 x - 1$ $(2x^3-7x^2-17x-3)/(2x+3)=x^2-5x-1$

Science

Math

Humanities

... and beyond

How do you divide $(2 x^{3} - 7 x^{2} - 17 x - 3) \div (2 x + 3)$ $(2x^3-7x^2-17x-3)div(2x+3)$ using long division?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you divide (2x3−7x2−17x−3)÷(2x+3)(2x^3-7x^2-17x-3)div(2x+3) using long division?

1 Answer

Explanation:

Related questions

Impact of this question

How do you divide $(2 x^{3} - 7 x^{2} - 17 x - 3) \div (2 x + 3)$ $(2x^3-7x^2-17x-3)div(2x+3)$ using long division?