How do you divide #(2x^3+9x^2+2x-21)div(x+3)# using synthetic division?

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Answer 1 · 2016-11-15T15:53:13

The quotient is #=(2x^2+3x-7)#

Let's do the long division

#color(white)(aaaa)##2x^3+9x^2+2x-21##color(white)(aaaa)##∣##x+3#

#color(white)(aaaa)##2x^3+6x^2##color(white)(aaaaaaaaaaaaa)##∣##2x^2+3x-7#

#color(white)(aaaaaa)##0+3x^2+2x#

#color(white)(aaaaaaaa)##+3x^2+9x#

#color(white)(aaaaaaaaaaa)##0-7x-21#

#color(white)(aaaaaaaaaaaaa)##-7x-21#

#color(white)(aaaaaaaaaaaaaaa)##-0-0#

The quotient is #=(2x^2+3x-7)#

no remainder