How do you divide $(2x^3+9x^2+2x-21)div(x+3)$ using synthetic division?

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Answer 1 · 2016-11-15T15:53:13

The quotient is $=(2x^2+3x-7)$

Let's do the long division

$color(white)(aaaa)$ $2x^3+9x^2+2x-21$ $color(white)(aaaa)$ $∣$ $x+3$

$color(white)(aaaa)$ $2x^3+6x^2$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $2x^2+3x-7$

$color(white)(aaaaaa)$ $0+3x^2+2x$

$color(white)(aaaaaaaa)$ $+3x^2+9x$

$color(white)(aaaaaaaaaaa)$ $0-7x-21$

$color(white)(aaaaaaaaaaaaa)$ $-7x-21$

$color(white)(aaaaaaaaaaaaaaa)$ $-0-0$

The quotient is $=(2x^2+3x-7)$

no remainder

How do you divide (2x^3+9x^2+2x-21)div(x+3)(2x^3+9x^2+2x-21)div(x+3) using synthetic division?