How do you divide $(2x^3+x+3 )/(x+1)$ ?

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Answer 1 · 2017-01-23T08:34:42

The answer is $=2x^2-2x+3$

You can do a long division

$color(white)(aaaa)$ $2x^3$ $color(white)(aaaaaaa)$ $x+3$ $color(white)(aaaaa)$ $|$ $x+1$

$color(white)(aaaa)$ $2x^3+2x^2$ $color(white)(aaaa)$ #color(white)(aaaaaaaa)|# $2x^2-2x+3$

$color(white)(aaaaa)$ $0-2x^2+x$

$color(white)(aaaaaaa)$ $-2x^2-2x$

$color(white)(aaaaaaaa)$ $-0+3x+3$

$color(white)(aaaaaaaaaaaa)$ $+3x+3$

$color(white)(aaaaaaaaaaaaa)$ $+0+0$

Therefore,

$(2x^3+2x^2)/(x+1)=2x^2-2x+3$

How do you divide (2x^3+x+3 )/(x+1)(2x^3+x+3 )/(x+1)?