How do you divide $(2x^4 + x^3 - x^2 + x - 1) ÷ (x + 7)$ ?

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Answer 1 · 2015-07-01T23:43:58

$(2x^4 +x^3 -x^2 +x -1)/(x+7) = 2x^3 - 13x^2 +90x -629 + 4402/(x+7)$

You use the process of long division.

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So,

$(2x^4 +x^3 -x^2 +x -1)/(x+7) = 2x^3 - 13x^2 +90x -629 + 4402/(x+7)$

Check:

$(x+7)(2x^3 - 13x^2 +90x -629 + 4402/(x+7)) =(x+7)( 2x^3 - 13x^2 +90x -629) + 4402$

$= 2x^4 -13x^3 +90x^2 -629x +14x^3 -91x^2 +630x -4403 +4402 = 2x^4 +x^3 -x^2 +x -1$

How do you divide (2x^4 + x^3 - x^2 + x - 1) ÷ (x + 7)(2x^4 + x^3 - x^2 + x - 1) ÷ (x + 7)?